I/O of integers in C
#include<stdio.h>
int main()
{
int c=5;
printf("Number=%d",c);
return 0;
}
Output
Number=5
Inside quotation of printf() there, is a conversion format string "%d" (for integer). If this conversion format string matches with remaining argument,i.e, c in this case, value of c is displayed.
#include<stdio.h>
int main()
{
int c;
printf("Enter a number\n");
scanf("%d",&c);
printf("Number=%d",c);
return 0;
}
Output
Enter a number
4
Number=4
The scanf() function is used to take input from user. In this program, the user is asked a input and value is stored in variable c. Note the '&' sign before c. &c denotes the address of c and value is stored in that address.
#include<stdio.h>
int main()
{
int c=5;
printf("Number=%d",c);
return 0;
}
Output
Number=5
Inside quotation of printf() there, is a conversion format string "%d" (for integer). If this conversion format string matches with remaining argument,i.e, c in this case, value of c is displayed.
#include<stdio.h>
int main()
{
int c;
printf("Enter a number\n");
scanf("%d",&c);
printf("Number=%d",c);
return 0;
}
Output
Enter a number
4
Number=4
The scanf() function is used to take input from user. In this program, the user is asked a input and value is stored in variable c. Note the '&' sign before c. &c denotes the address of c and value is stored in that address.
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